Answer: Binary Secret #323

The secret message is:

Code on

Row by row

Row	Bulbs	Add the ‘on’ numbers	Character
1	01000011	64 + 2 + 1 = 67	C
2	01101111	64 + 32 + 8 + 4 + 2 + 1 = 111	o
3	01100100	64 + 32 + 4 = 100	d
4	01100101	64 + 32 + 4 + 1 = 101	e
5	00100000	32 = 32	a space
6	01101111	64 + 32 + 8 + 4 + 2 + 1 = 111	o
7	01101110	64 + 32 + 8 + 4 + 2 = 110	n

Crack it with Python

Python can do the adding for you. int(code, 2) reads a string of 1s and 0s as a binary number. Then chr() turns the number into its character.

secret = [
    "01000011",
    "01101111",
    "01100100",
    "01100101",
    "00100000",
    "01101111",
    "01101110",
]
message = ""
for code in secret:
    number = int(code, 2)
    message = message + chr(number)
print(message)

When you run it, it prints:

Code on