The answer is D. The program prints:
42
This answer was checked by running the program for real.
Why?
The loop remembers the biggest number it has seen so far, and replaces it whenever it finds a bigger one. This is how computers find the maximum.
Trace table
A trace table follows the program step by step. Here’s this one:
| n | n > biggest? | biggest |
|---|---|---|
| 41 | yes | 41 |
| 42 | yes | 42 |
| 26 | no | 42 |
| 40 | no | 42 |
| 25 | no | 42 |
The code again
numbers = [41, 42, 26, 40, 25]
biggest = 0
for n in numbers:
if n > biggest:
biggest = n
print(biggest)
Try it: change one number in the program and predict the new output before you run it.