The answer is D. The program prints:
57
This answer was checked by running the program for real.
Why?
The loop remembers the biggest number it has seen so far, and replaces it whenever it finds a bigger one. This is how computers find the maximum.
Trace table
A trace table follows the program step by step. Here’s this one:
| n | n > biggest? | biggest |
|---|---|---|
| 8 | yes | 8 |
| 20 | yes | 20 |
| 57 | yes | 57 |
| 28 | no | 57 |
| 42 | no | 57 |
The code again
numbers = [8, 20, 57, 28, 42]
biggest = 0
for n in numbers:
if n > biggest:
biggest = n
print(biggest)
Try it: change one number in the program and predict the new output before you run it.