The answer is B. The program prints:
### ###

Why?
The outer loop runs 2 times (one per row). Inside it, the inner loop adds 3 symbols to line. So you get 2 rows of 3.
Trace table
A trace table follows the program step by step. Here’s this one:
| row | line printed |
|---|---|
| 0 | ### |
| 1 | ### |
The code again
for row in range(2):
line = ""
for col in range(3):
line = line + "#"
print(line)
Try it: change one number in the program and predict the new output before you run it.